Make a box-and-whisker plot for each data set. Area in 1,000 mi2 of 13 western states. 122, 164, 71, 98, 84, 147, 114, 111, 98, 85, 104, 71, 77 median: __________ lower quartile: ________ upper quartile: _________

iohanetc 2020-10-28 Answered
Make a box-and-whisker plot for each data set.
Area in 1,000 mi2 of 13 western states.
122, 164, 71, 98, 84, 147, 114, 111, 98, 85, 104, 71, 77
median: __________
lower quartile: ________
upper quartile: _________
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

comentezq
Answered 2020-10-29 Author has 106 answers

To find the median, you must first order the data values from least to greatest:
71, 71, 77, 84, 85, 98, 98, 104, 111, 114, 122, 147, 164
The median is the middle value so the median is 98.
The lower quartile is the median of the first half of the data. The first half of the data does not include the median of the set so the first half of the data is:
71, 71, 77, 84, 85, 98
Since the first half of the data has an even number of values, the median of the first half is the average of the two middle values of 77 and 84. The median is then 77+842=80.5 so the lower quartile is 80.5.
The upper quartile is the median of the second half of the data. The second half of the data does not include the median of the set so the second half of the data is:
104, 111, 114, 122, 147, 164
Since the second half of the data has an even number of values, the median of the second half is the average of the two middle values of 114 and 122. The median is then (114+122)2=118 so the upper quartile is 118.
To make the box-and-whisker plot, plot the minimum of 71, the lower quartile of 80.5, the median of 98, the upper quartile of 118, and the maximum of 164. Draw a box that has sides at the lower and upper quartiles. Draw a vertical segment in the box passing through the median. Then draw segments from the minimum to the lower quartile and from the upper quartile to the maximum:
[Pic]

Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

You might be interested in

asked 2021-02-23
Interpreting z-scores: Complete the following statements using your knowledge about z-scores.
a. If the data is weight, the z-score for someone who is overweight would be
-positive
-negative
-zero
b. If the data is IQ test scores, an individual with a negative z-score would have a
-high IQ
-low IQ
-average IQ
c. If the data is time spent watching TV, an individual with a z-score of zero would
-watch very little TV
-watch a lot of TV
-watch the average amount of TV
d. If the data is annual salary in the U.S and the population is all legally employed people in the U.S., the z-scores of people who make minimum wage would be
-positive
-negative
-zero
asked 2021-08-16
A furniture store is offering a series discount of 25/10 on a dining room table with a list price of $5690. Find the net cost after the series discount. Use the method of calculating series separately.
answers $1991.50
$5547.75
$3840.75
$3698.50
asked 2022-07-05
Show, that if f n f and f n g is μ-convergent, then f = g almost everywhere on X
Hint
Use the fact, that:
{ x X : f ( x ) g ( x ) } = m = 1 { x X : | f ( x ) g ( x ) | 1 m }
So, I don't know how to use that hint. μ convergent means (correct me if I'm wrong), that
f n f  is  μ  convergent μ ( { x X : ε lim n | f n ( x ) f ( x ) | > ε } ) = 0
So I don't see it how the hint should be used.
It is not written what kind of measure our μ is though, usually when there's nothing written we assume it's a Lebesgue measure, but I don't know if that has to be the case here
asked 2022-03-22
Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10significance level to test for a difference between the measurements from the two arms. What can be​ concluded?
Right arm: 146 137 140 132 132
Left-arm: 183 172 179 156 149
In this​ example, μd is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test?
Identify the test statistic.
Identify the​ P-value.
asked 2020-11-22
Which procedure(s) decrease(s) the random error of a measure-ment:
(1) taking the average of more measurements,
(2) calibrat-ing the instrument,
(3) taking fewer measurements? Explain
asked 2022-05-21
Factorising this formula
I came across this simplification in an iTunes U calculus course.
1 x 0 + δ x 1 x 0 δ x = 1 δ x ( x 0 ( x 0 + δ x ) ( x 0 + δ x ) x 0 )
I didn't understand how this was done. I can see the denominator being taken out for 1 δ x but do not understand the remainder. Can someone give me some guidance? Thanks
asked 2022-02-02
How do you evaluate x3y if x=3 and y=2?