Marianna is painting a ramp for the school play that is in the shape of a right triangular prism. The ramp has the dimensions shown. She will not pain

Marianna is painting a ramp for the school play that is in the shape of a right triangular prism. The ramp has the dimensions shown. She will not pain the back or bottom surfaces of the ramp.
Each can of paint covers 1,000 square inches. What is the fewest number of full cans of paint Marianna will need? Circle the minimum number of cans.
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

grbavit

Since Marianna will not paint the back or the bottom surfaces of the ramp, she will only paint the rectangular face on top and the two triangular faces on the sides.
The rectangular face has dimensions of 59.5 inches by 50 inches so its area is $59.5\left(50\right)=2975$ square inches.
The triangular faces have dimensions of 14 inches by 48 inches so each one has an area of $\frac{1}{2}\left(48\right)\left(14\right)=24\left(14\right)=336$ square inches.
The total area that Marianna will paint is then $2975+2\left(336\right)=2975+672=3647$ square inches.
Since each can covers 1,000 square inches and $\frac{3647}{1000}=3.647$, then she will need 4 full cans of paint to have enough paint.