Find the sum of the first 3 terms of a geometric sequence with a= 99 and r= - 4/3

Jazmyn Saunders

Jazmyn Saunders

Answered question

2022-09-01

Find the sum of the first 3 terms of a geometric sequence with a= 99 and r= - 4/3

Answer & Explanation

Aleah Harrell

Aleah Harrell

Beginner2022-09-02Added 18 answers

A geometric sequence is a sequence of the form a , a r , a r 2 , a r 3 , a r 4 ,..
The number a is the first term, and r is the common ratio of thesequence. The nth term of a geometric sequence is given by a n = a r n 1
For the geometric sequence a n = a r n 1 , the nth partial sum
S n = a + a r + a r 2 + a r 3 + a r 4 + . . . + a r n 1 ( r 1 )   i s   g i v e n   b y   S n = a 1 r n 1 r
So the sum of the first 3 terms of a geometric sequence with a=99 and r = 4 3 is:
S 3 = 99 1 ( 4 3 ) 3 1 ( 4 3 ) = 99 91 / 27 7 / 3 = 99 13 9 = 143
tophergopher3wo

tophergopher3wo

Beginner2022-09-03Added 5 answers

Thus, the general form of a geometric sequence is
a , a r , a r 2 , a r 3 , a r 4 ,...
and that of a geometric series is
a + a r + a r 2 + a r 3 + a r 4
where r 0 is the common ratio and ais a scale factor, equal to the sequence's start value.
a=99,
r = 4 3
a + a r + a r 2 + a r 3 + a r 4
first three term
99 + 99 ( 4 3 ) + 99 ( 4 3 ) 2 = 99 ( 1 4 3 + 16 9 ) = 143

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?