Reeves
2020-11-22
Answered

A scuba diver dove from the surface of the ocean to an elevation of $-79\frac{9}{10}$ feet at a rate of - 18.8 feet per minute. After spending 12.75 minutes at that elevation, the diver ascended to an elevation of $-28\frac{9}{10}$ feet. The total time for the dive so far was $19\frac{1}{8}$ . minutes. What was the rate of change in the diver's elevation during the ascent?

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Clelioo

Answered 2020-11-23
Author has **88** answers

The rate of change in the diver's elevation during the ascent is: rate of change in elevation during descent = time spend ascending/change in elevation during ascent

The change in the diver's elevation during the ascent is the diver's final elevation minus the diver's initial position. The diver's final elevation is

change in elevation=final elevation−initial elevation

You know the total time it took the diver to descend, stay at the elevation, and then ascend. The time it took the diver to ascend is then the total time minus the time to descend minus the time spent at the elevation.

You weren't given the time it took the diver to descend but you were given how far the diver descended and at what rate. The diver descended to an elevation of

Since distance = (rate)(time), dividing both sides by the rate then gives time=distance/rate.

The time it took the diver to descend is then:

The time it took the diver to ascend is then the total time of

time to ascend

You now have everything you need to find the rate of change in elevation:

rate of change in elevation during descent= time spend ascending/change in elevation during ascent

The rate of change in the diver's elevation during the ascent was then 24 feet per minute.

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