An athlete must travel 30 km in his last 5 days of preparation for a competition. the first day runs

ddaeeric
2021-02-13
Answered

An athlete must travel 30 km in his last 5 days of preparation for a competition. the first day runs

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Macsen Nixon

Answered 2021-02-14
Author has **117** answers

The total distance the athlete traveled over the four days is the sum of the four given fractions.

To add fractions, you must first rewrite them to have a common denominator.

For the fractions,

To find a common denominator, you then need to find the least common multiple of 2, 3, 4, and 6.

Since 2 and 3 are factors of 6, the lowest common multiply of 2, 3, 4, and 6 is the lowest common multiple of 4 and 6.

The first few multiples of 4 are 4, 8, 12, and 16, The first few multiples of 6 are 6, 12, 18, and 24.

The least common multiple of 4 and 6 is then 12.

You then need to rewrite the fractions to have a denominator of 12:

Now that the fractions have a common denominator, you can add them to find the total distance that the athlete traveled.

To add the fractions, add the numerators and leave the denominator the same:

To convert an improper fraction to a mixed number, determine how many times the denominator goes into the numerator. 12 goes into 317 twenty-six times with a remainder of 5 since

Therefore

The athlete then traveled a total distance of

asked 2022-06-21

Let $X$ be a set and $\mathcal{F}$ a $\sigma $-algebra. Does there exist a topological space $U$ and a map $f:X\to U$ such that $f$ is $\mathcal{F},\mathcal{B}$-measurable and $\sigma (f)=\mathcal{F}$? Here $\mathcal{B}$ is the Borel $\sigma $-algebra of $U$.

Of course, this is trivial if every $\sigma $-algebra on a set is the Borel $\sigma $-algebra with respect to some topology on the set. But this needn't be true. This is a weaker problem.

Of course, this is trivial if every $\sigma $-algebra on a set is the Borel $\sigma $-algebra with respect to some topology on the set. But this needn't be true. This is a weaker problem.

asked 2022-05-19

Clarification about percentage calculus

Why if we want to know what percentage of 16 is 4 we do

4/16

and not

16/4

?

4/16 gives you the answer, because it's equal to 0.25, that is equal to 25%, while 16/4 doesn't (I guess); but I don't understand the logic. It seems more natural to me to do 16/4, because if I want to know the percentage I would split the 16 by 4 to know how many parts does the 4 create (in my logic the number of parts created define the percentage). So if I try to do 16/4 I get 4, but then I don't know how to go on to get 25%. Maybe there's a way to obtain the result in the way I'm proposing but I don't know it.

I hope my question doesn't sound stupid, but this is one of the many basic things that I'm lacking in math to fully understand its logic.

Why if we want to know what percentage of 16 is 4 we do

4/16

and not

16/4

?

4/16 gives you the answer, because it's equal to 0.25, that is equal to 25%, while 16/4 doesn't (I guess); but I don't understand the logic. It seems more natural to me to do 16/4, because if I want to know the percentage I would split the 16 by 4 to know how many parts does the 4 create (in my logic the number of parts created define the percentage). So if I try to do 16/4 I get 4, but then I don't know how to go on to get 25%. Maybe there's a way to obtain the result in the way I'm proposing but I don't know it.

I hope my question doesn't sound stupid, but this is one of the many basic things that I'm lacking in math to fully understand its logic.

asked 2021-09-08

A bank finds that the estimated proportion of clients defaulting on a loan, given the interest rate is below $15\mathrm{\%}$ , is 0.34, They also find that the estimated proportion of clients defaulting on a loan, given the interest is greater than or equal to $15\mathrm{\%}$ , is 0.52.

a) What is the odds ratio of defaulting given the interest rate is greater than or equal to$15\mathrm{\%}$ relative to the interest rate is lower than $15\mathrm{\%}$ ? Interpret this odds ratio.

b) If we were to analyze this data using the following logistic regression model, what are the estimates of$\beta}_{0$ and $\beta}_{1$ ? Show your work.

$lg\left\{\left(\frac{p}{1-p}\right)\right\}={\beta}_{0}+{\beta}_{1}x$

Where p is the probability of defaulting on a loan and x is an indicator variable that is 1 when the interest rate is greater than or equal to$15\mathrm{\%}$ and 0 when the interest rate is less than $15\mathrm{\%}$ .

a) What is the odds ratio of defaulting given the interest rate is greater than or equal to

b) If we were to analyze this data using the following logistic regression model, what are the estimates of

Where p is the probability of defaulting on a loan and x is an indicator variable that is 1 when the interest rate is greater than or equal to

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$\frac{8}{9}\times \frac{7}{4}=$ ?

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What is the eighth term given the sequence: $+896,-448,+224,-112,\cdots$ ?

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One cake recipe calls for $\frac{2}{3}$ cup of sugar. Another recipe calls for $\frac{1}{4}$ cups of sugar. How many cups of sugar are needed to make both cakes?

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The ratio of the sum used of nth term of 2 Aps is $(7n+1):(4n+27)$ .

Find the ratio of the n-th term..?

Find the ratio of the n-th term..?