A 62.1kg mal ice skater is facing a 42.8kg female ice skater. they are at rest on the ice they push off each other and move in opposite directions. The female skater moves backwards with a speed of 3.11 m/s. determine the post-impulse speed of the male skater.

kalkulusk2

kalkulusk2

Open question

2022-08-31

A 62.1kg mal ice skater is facing a 42.8kg female ice skater. they are at rest on theice they push off each other and move in opposite directions. The female skatermoves backwards with a speed of 3.11 m/s. determine the post-impulse speed of the male skater.

Answer & Explanation

Coraducci0d

Coraducci0d

Beginner2022-09-01Added 8 answers

mass of male ice skater
m 1 = 62.1 k g
mass of female ice skater
m 2 = 42.0 k g
Initially both are at rest i.e
u 1 = u 2 = 0
Initial, linear mo.
p i = m 1 u 1 + m 2 u 2 = 0 + 0 p i = 0
Now, they starts moving in opposite direction and speeds are below
speed of female ice skates
v 2 = 3.11 m / s e c (opposite to male skates)
let the speed of male ice skater
Final, total linear mo.
ρ f = m 1 v 1 + m 2 v 2 = 62.1 × v + 42.0 ( 3.11 )
ρ f = 62.1 v 133.11
From conservation of linear momentum
ρ i = ρ f
0 = 62.1 v 133.11 62.1 v = 133.11 v = 2.14 m / s e c
Hence, the speed of male ice skater will be 2.14m/sec

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Advanced Physics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?