Find the inverse of alpha^(38) in F=ZZ_2[x]/<x^4+x+1>

boske9s

boske9s

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2022-08-31

Find the inverse of α 38 in F = Z 2 [ x ] / x 4 + x + 1

Answer & Explanation

etapi9a

etapi9a

Beginner2022-09-01Added 12 answers

You've got F = F 16 and is visibly a generator of the multiplicative group of order 15. So α 38 = α ( 38 ) mod 15 = α 7 which equals 1 + α + α 3

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