The smallest positive integer in the set {6u+9v:u,v=integers} is 1. My thoughts: false. there is no value of u and v (positive or negative) that could result in a remainder of 1. Smallest positive I get is 3. Solid foundation to prove it?

chemicars8

chemicars8

Open question

2022-08-26

The smallest positive integer in the set { 6 u + 9 v : u , v = integers } is 1.
My thoughts: false. there is no value of u and v (positive or negative) that could result in a remainder of 1. Smallest positive I get is 3. Solid foundation to prove it?

Answer & Explanation

Heidy Phelps

Heidy Phelps

Beginner2022-08-27Added 4 answers

But in this case, just note that every number of the form 6 u + 9 v is divisible by 3, since
6 u + 9 v = 3 ( 2 u + 3 v )
But 1 isn't.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?