How would I find where the interval in which f increases and decreases in the following function. f(x)=|4-x^2|

Angela Arnold

Angela Arnold

Open question

2022-08-26

Absolute value f interval?
How would I find where the interval in which f increases and decreases in the following function.
f ( x ) =∣ 4 x 2
What would I do find the zero
I know f ( x ) = { 4 x 2 for | x | < 2 x 2 4 for | x | > 2
I suspect there are zeroes at 2 and -2 looking at the graph of the function. But how would find the zeroes.So that I can find the f interval.

Answer & Explanation

Blaine Ross

Blaine Ross

Beginner2022-08-27Added 4 answers

Step 1
The curve y = | 4 x 2 | is symmetric about the y-axis. So if we understand its behaviour for x 0, we will know everything.
We have | 4 x 2 | = 4 x 2 if | x | 2, and | 4 x 2 | = x 2 4 if | x | > 2.
It is I think clear that 4 x 2 is decreasing in the interval [0,2]. It is also clear that x 2 4 is increasing in the interval [ 2 , ]. erivatives can be used to show these things, but they are not necessary.
Step 2
So our function is decreasing in [0,2] and increasing in [ 2 , ).
Now look at the reflection in the y-axis. We conclude that our function is decreasing in ( , 2 ] and increasing in [-2,0].
Skylar French

Skylar French

Beginner2022-08-28Added 7 answers

Step 1
Look at the derivative: f ( x ) = { 2 x for | x | < 2 2 x for | x | > 2 }
Step 2
So f is decreasing in the intervalls ( , 2 ] and [0,2] and increasing in the intervalls [-2,0] and [ 2 , )

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