explain what steps you would use to simplify

OlmekinjP
2021-03-05
Answered

explain what steps you would use to simplify

You can still ask an expert for help

yunitsiL

Answered 2021-03-06
Author has **108** answers

The first step would be to solve everything in the brackets.

After that you solve the multiplication.

And then you solve the addition.

asked 2021-08-11

A ball is tossed upward from the ground. Its height in feet above ground after t seconds is given by the function $h\left(t\right)=-16{t}^{2}+24t$ . Find the maximum height of the ball and the number of seconds it took for the ball to reach the maximum height.

asked 2021-01-04

Write in words how to read each of the following out loud.

a. $\{x\in {R}^{\prime}\mid 0<x<1\}$

b. $\{x\in R\mid x\le 0{\textstyle \phantom{\rule{1em}{0ex}}}\text{or}{\textstyle \phantom{\rule{1em}{0ex}}}x\Rightarrow 1\}$

c. $\{n\in Z\mid n\text{}is\text{}a\text{}factor\text{}of\text{}6\}$

d. $\{n\in Z\cdot \mid n\text{}is\text{}a\text{}factor\text{}of\text{}6\}$

asked 2021-12-17

The given ratio is in the simplest form or not.

The given ratio in the simplest form.

The simplest form of the given ratio in two other ways.

Given information:

The ratio given in the question:

8 to 6

The given ratio in the simplest form.

The simplest form of the given ratio in two other ways.

Given information:

The ratio given in the question:

8 to 6

asked 2022-06-25

Finding derivative $f(x)=\frac{2}{{x}^{3}}$

I have to find the derivative and the slope at a=6

The function is $f(x)=\frac{2}{{x}^{3}}$

I have to find the answer using the formula,

${f}^{\prime}(x)=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{f(x+\mathrm{\Delta}x)-f(x)}{\mathrm{\Delta}x}$

I tried getting rid of the denominator, but I think I'm getting mixed up somewhere.

The answer book says the slope is $\frac{-1}{216}$

Here's what I've done,

${f}^{\prime}(x)=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{f(x+\mathrm{\Delta}x)-f(x)}{\mathrm{\Delta}x}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{\frac{2}{(x+\mathrm{\Delta}x{)}^{3}}-\frac{2}{{x}^{3}}}{\mathrm{\Delta}x}\phantom{\rule{0ex}{0ex}}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{(\frac{2}{(x+\mathrm{\Delta}x{)}^{3}}-\frac{2}{{x}^{3}})((x+\mathrm{\Delta}x{)}^{3}({x}^{3}))}{\mathrm{\Delta}x((x+\mathrm{\Delta}x{)}^{3}({x}^{3}))}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{2({x}^{3})-2(x+\mathrm{\Delta}x{)}^{3}}{\mathrm{\Delta}x(x+\mathrm{\Delta}x{)}^{3}({x}^{3})}$

To cancel out the denominator.

Did I do this right??

Should I now expand the parentheses and cancel things out??

Would I still get the same answer as the answer book??(Because the answer book have made a typo once before).

Thanks

I have to find the derivative and the slope at a=6

The function is $f(x)=\frac{2}{{x}^{3}}$

I have to find the answer using the formula,

${f}^{\prime}(x)=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{f(x+\mathrm{\Delta}x)-f(x)}{\mathrm{\Delta}x}$

I tried getting rid of the denominator, but I think I'm getting mixed up somewhere.

The answer book says the slope is $\frac{-1}{216}$

Here's what I've done,

${f}^{\prime}(x)=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{f(x+\mathrm{\Delta}x)-f(x)}{\mathrm{\Delta}x}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{\frac{2}{(x+\mathrm{\Delta}x{)}^{3}}-\frac{2}{{x}^{3}}}{\mathrm{\Delta}x}\phantom{\rule{0ex}{0ex}}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{(\frac{2}{(x+\mathrm{\Delta}x{)}^{3}}-\frac{2}{{x}^{3}})((x+\mathrm{\Delta}x{)}^{3}({x}^{3}))}{\mathrm{\Delta}x((x+\mathrm{\Delta}x{)}^{3}({x}^{3}))}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=\underset{\mathrm{\Delta}x\to 0}{lim}\frac{2({x}^{3})-2(x+\mathrm{\Delta}x{)}^{3}}{\mathrm{\Delta}x(x+\mathrm{\Delta}x{)}^{3}({x}^{3})}$

To cancel out the denominator.

Did I do this right??

Should I now expand the parentheses and cancel things out??

Would I still get the same answer as the answer book??(Because the answer book have made a typo once before).

Thanks

asked 2021-02-05

2.37 - (-1.55) - 2.48

asked 2022-07-29

Determine:

$27{x}^{2}-39x-10\phantom{\rule{0ex}{0ex}}3({x}^{2}-3x+5)-2({x}^{2}-2x+1)\phantom{\rule{0ex}{0ex}}\frac{4}{5}y+\frac{1}{4}(y-5)=y+\frac{1}{8}$

$27{x}^{2}-39x-10\phantom{\rule{0ex}{0ex}}3({x}^{2}-3x+5)-2({x}^{2}-2x+1)\phantom{\rule{0ex}{0ex}}\frac{4}{5}y+\frac{1}{4}(y-5)=y+\frac{1}{8}$

asked 2021-09-10

TD Canada Trust discovers that the estimated proportion of clients defaulting on a loan, if the interest rate is lower than$15\mathrm{\%}$ , is 0.34. They also discover that the estimated proportion of clients defaulting on a loan, given the interest is greater than or equal to $15\mathrm{\%}$ , is 0.52.

a) What is the odds ratio of defaulting given the interest rate is greater than or equal to$15\mathrm{\%}$ relative to the interest rate is lower than $15\mathrm{\%}$ ? Interpret this odds ratio.

b) If we were to analyze this data using the following logistic regression model, what are the estimates of$\beta}_{0$ and $\beta}_{1$ ? Showyourwork.

l$\mathrm{log}(\frac{p}{1}-p)={\beta}_{0}+{\beta}_{1}x$

(Where p is the probability of defaulting on a loan and x is an indicator variable that is 1 when the interest rate is greater than or equal to$15\mathrm{\%}$ and 0 when the interest rate is less than $15\mathrm{\%}$ )

a) What is the odds ratio of defaulting given the interest rate is greater than or equal to

b) If we were to analyze this data using the following logistic regression model, what are the estimates of

l

(Where p is the probability of defaulting on a loan and x is an indicator variable that is 1 when the interest rate is greater than or equal to