Given v_1=(1,0,1,2)^T, v_2=(0,1,1,0)^T, v_3=(−1,2,1,0)^T, v_4=(0,0,1,0)^T. Prove that v_1,v_2,v_3,v_4 form a basis of RR^4

torfuqx

torfuqx

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2022-08-21

Given v 1 = ( 1 , 0 , 1 , 2 ) T , v 2 = ( 0 , 1 , 1 , 0 ) T , v 3 = ( 1 , 2 , 1 , 0 ) T , v 4 = ( 0 , 0 , 1 , 0 ) T
Prove that v 1 , v 2 , v 3 , v 4 form a basis of R 4

Answer & Explanation

klunnalegj6

klunnalegj6

Beginner2022-08-22Added 7 answers

n vectors in R n are linearly independent if and only if the determinant of the matrix formed by taking the vectors as its columns is non-zero. In this case, it is rather easy to calculate that that determinant is −2 (not 0), so the 4 vectors are linearly independent.
cinearth3

cinearth3

Beginner2022-08-23Added 1 answers

What you thought is not correct ! For example ( 3 , 1 ) and ( 0 , 6 ) form a basis of R 2 .
You only have to show that v 1 , v 2 , v 3 , v 4 are linearly independent.

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