What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses? aa bb cc dd * AA BB CC DD

ignizeddyug

ignizeddyug

Open question

2022-08-19

What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses?
aa bb cc dd × AA BB CC DD

Answer & Explanation

riveExedeer

riveExedeer

Beginner2022-08-20Added 5 answers

If both parents have the genotype Aa Bb Cc Dd, their phenotype is determined by the dominant alleles for these four traits. If we observe on trait, we have 3 times bigger possibility for a dominant (AA, Aa, and Aa) than recessive phenotype (aa). Since we observe four different traits, the probability for an ofring to look like their parents is (3)/(4)*(3)/(4)*(3)/(4)*(3)/(4)=0,32. The number of possible phenotypes is 2 for each of the 4 traits (for example Aa and aa for the first trait), which makes it 16 (2 2 2 * 2).

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school probability

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?