What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses? Aa Bb Cc Dd * aa bb cc dd

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2022-08-20

What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four crosses? How many phenotypically different kinds of progeny could potentially result from each of the four crosses?
Aa Bb Cc Dd × aa bb cc dd

Answer & Explanation

Rocco Juarez

Rocco Juarez

Beginner2022-08-21Added 8 answers

One parent has the genotype Aa Bb Cc Dd while hte other has aa bb cc dd. If an of<img src="ring looks like the heterozygous parent, it must inherit dominant alleles (A,B,C, and D) from the first parent, while the recessive alleles will be inherited from the second parent. The probability for this to occur is 12121212=116.
If an ofspring looks like the homozygous recessive parent, it must inherit recessive alleles (a,b,c, and d) from the first parent. The probability is 12121212=116.
Thus, the possibility for a child to look like either of his parents is 116+116.
The number of possible phenotypes is 2 for each of the 4 trails (for example Aa and aa for the first trait), which makes it 16 (2 2 2*2).

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