What are the mean and standard deviation of {34, 98, 20, -1200, -90}?

Trevor Rush

Trevor Rush

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2022-08-14

What are the mean and standard deviation of {34, 98, 20, -1200, -90}?

Answer & Explanation

Jaxson White

Jaxson White

Beginner2022-08-15Added 15 answers

Explanation:
Calculate the mean as the sum of the numbers divided by the number of observations
M e a n = 34 + 98 + 20 1200 90 5 = 227.6
Calculate the standard deviation as the square root of the sum of the squared difference each observation and the mean divided by the number of observations.
Standard deviation
= ( 34 227.6 ) 2 + ( 98 227.6 ) 2 + ( 20 227.6 ) 2 + ( 1200 227.6 ) 2 + ( 90 227.6 ) 2 5 = 489.9492
balafiavatv

balafiavatv

Beginner2022-08-16Added 2 answers

Data: S={34,98,20,-1200,-90}
Mean: s 5 = 227.6
Variance square differences are ( 34 ( 227.6 ) ) 2 = 68434.56
( 98 ( 227.6 ) ) 2 = 106015.36 , ( 20 ( 227.6 ) ) 2 = 61305.76 ,
( 1200 ( 227.6 ) ) 2 = 945561.76 , ( 90 ( 227.6 ) ) 2 = 18933.76
Average variance square differences is
σ 2 = 1200251.2 5 = 240050.24
Standard deviation is σ 2 = 489.9492

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