# Distance between (9,2,0) and (0,6,0)?

Distance between (9,2,0) and (0,6,0)?
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Payton Mcbride
Use the 3-d version of the distance formula
$\mid \overline{\underline{\frac{a}{a}d=\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}+{\left({z}_{2}-{z}_{1}\right)}^{2}}\frac{a}{a}\mid }}$
where $\left({x}_{1},{y}_{1},{z}_{1}\right)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}\left({x}_{2},{y}_{2},{z}_{2}\right)\phantom{\rule{1ex}{0ex}}\text{are 2 coordinate points}$
here the 2 points are (9 ,2 ,0) and (0 ,6 ,0)
let $\left({x}_{1},{y}_{1},{z}_{1}\right)=\left(9,2,0\right)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}\left({x}_{2},{y}_{2},{z}_{2}\right)=\left(0,6,0\right)$
$d=\sqrt{{\left(0-9\right)}^{2}+{\left(6-2\right)}^{2}+{0}^{2}}=\sqrt{81+16}=\sqrt{97}\approx 9.849$