Show that a path going from one vertex of the unit square (in C) to its opposite and a second path going between the other pair of opposite vertices must intersect. By path I mean continuous function f:[0,1]->C with f(0) one vertex and f(1) the other. [EDIT] Both are paths in the unit square (no going outside)

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The solution of a differential equation y′′+3y′+2y=0 is of the form
A) $c_1{e}^x+c_2{e}^{2x}$
B) $c_1{e}^{-<!--\; -\; -->x}+c_2{e}^{3x}$
C) $c_1{e}^{-<!--\; -\; -->x}+c_2{e}^{-<!--\; -\; -->2x}$
D) $c_1{e}^{-<!--\; -\; -->2x}+c_2{2}^{-<!--\; -\; -->x}$

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A. 4.2
B. 4.4
C. 4.7
D. 5.1

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The differential coefficient of $\sec \left({\tan }^{-1}\left(x\right)\right)$.