# Hi! This is a test question. Please enjoy it reponsibly. Testing testing. fx==int_{infty}^{-infty} fxi​(e^2pixi x)dxi

Question
Differential equations
Hi! This is a test question. Please enjoy it reponsibly.
Testing testing.
$$\displaystyle{f}{x}=={\int_{{\infty}}^{{-\infty}}}{f}\xi​{\left({e}^{{2}}\pi\xi{x}\right)}{d}\xi$$

2021-02-01
Sup, bruh?
Let $$\displaystyle{a}={b}+{1}{a}={b}+{1}.$$ Then
$$\displaystyle{\left({a}−{b}\right)}{a}={\left({a}-{b}\right)}{\left({b}+{1}\right)}$$
$$\displaystyle{a}^{{{2}}}-{a}{b}={a}{b}+{a}-{b}^{{{2}}}-{b}^{{{2}}}-{b}$$
$$\displaystyle{a}^{{{2}}}-{a}{b}-{a}={a}{b}+{a}-{a}-{b}^{{{2}}}-{b}^{{{2}}}-{b}$$
$$\displaystyle{a}{\left({a}-{b}-{1}\right)}={b}{\left({a}-{b}-{1}\right)}$$
$$\displaystyle{a}={b}$$
$$\displaystyle{b}+{1}={b}$$
Hence 1=0

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