How to, using Taylor series approximation , estimate the value of pi, when arctan(x) ~~ x-x3/3+x5/5-x7/7 ?

trokusr

trokusr

Answered question

2022-08-14

How to, using Taylor series approximation , estimate the value of π , when arctan ( x ) x x 3 / 3 + x 5 / 5 x 7 / 7?

Answer & Explanation

Cindy Walls

Cindy Walls

Beginner2022-08-15Added 10 answers

Let x=1
π 4 = arctan ( 1 ) = ( 1 ) ( 1 ) 3 3 + ( 1 ) 5 5 ( 1 ) 7 7
π 4 = 1 1 3 + 1 5 1 7
π = 4 ( 1 1 3 + 1 5 1 7 )
Maghrabimh

Maghrabimh

Beginner2022-08-16Added 5 answers

Using the given Taylor Series approximation (truncation) we have:
arctan x x x 3 3 + x 5 5 x 7 7
Using the well known result:
tan ( π 4 ) = 1 arctan 1 = π 4
So, substituting x=1 into the given TS we have:
π 4 1 1 3 + 1 5 1 7
= 3 5 7 5 7 + 3 7 3 5 3 5 7
= 105 35 + 21 15 105
= 76 105
Thus:
π 4 76 105
= 304 105
= 2.90 ( 3 s f )
A (not so) interesting fact is that using this particular Taylor Series and method to approximate π tp 3 significant figures (or 2 decimal places) requires 147 terms of the sequence, as is therefore a particularly inefficient method to estimate π

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