cofak48
2022-08-12
Answered

If we have a light ray ${x}^{\mu}$ with velocity $c$, what is ${c}^{0}$ (the time component)?

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asked 2022-07-13

It is experimentally known that the equation of motion for a charge $e$ moving in a static electric field $\mathbf{E}$ is given by:

$\frac{\mathrm{d}}{\mathrm{d}t}(\gamma m\mathbf{v})=e\mathbf{E}$

Is it possible to show this using just Newton's laws of motion for the proper frame of $e$, symmetry arguments, the Lorentz transformations and other additional principles?

$\frac{\mathrm{d}}{\mathrm{d}t}(\gamma m\mathbf{v})=e\mathbf{E}$

Is it possible to show this using just Newton's laws of motion for the proper frame of $e$, symmetry arguments, the Lorentz transformations and other additional principles?

asked 2022-05-17

Chosing a reference frame in which the Earth is at rest and doesn't rotate

1) Does anybody know of such a publication?

2) I know that even such speeds of ${10}^{18}$ m/s are not in contradiction with relativity because a limiting velocity only exists for exchange of information, which apparantly does not occur.

1) Does anybody know of such a publication?

2) I know that even such speeds of ${10}^{18}$ m/s are not in contradiction with relativity because a limiting velocity only exists for exchange of information, which apparantly does not occur.

asked 2022-08-12

Have any known experiments ruled out travelling faster than the speed of light? Or is this just a widely accepted theory?

asked 2022-07-31

At one poinn a pipeline the water's spced is 3.00 ms and the gange pressure is

Sx l0 Pa. Find the gauge peessure al a seoond point in the line, 11.0 m bower thas

the first, if the pipe dianeter at the seccond point is twice that at the first.

asked 2022-08-19

A source of light pulses moves with speed v directly away from an observer at rest in an inertial frame. Let $\mathrm{\Delta}{t}_{e}$ be the time between the emission of pulses, and $\mathrm{\Delta}{t}_{o}$ be the time between their reception at the observer. Show that $\mathrm{\Delta}{t}_{o}=\mathrm{\Delta}{t}_{e}+v\mathrm{\Delta}{t}_{e}$.

Based on my understanding of special relativity, the space-time interval between two events as measured from two inertial frames of reference should be the same. Therefore,

$\mathrm{\Delta}{t}_{e}^{2}=\mathrm{\Delta}{t}_{o}^{2}-\mathrm{\Delta}{x}^{2}$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}\mathrm{\Delta}{t}_{e}^{2}=\mathrm{\Delta}{t}_{o}^{2}-{v}^{2}\mathrm{\Delta}{t}_{o}^{2}$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}\mathrm{\Delta}{t}_{o}=(1-{v}^{2}{)}^{-1/2}\mathrm{\Delta}{t}_{e}$

which is not the same relation. What is wrong with my reasoning?

Based on my understanding of special relativity, the space-time interval between two events as measured from two inertial frames of reference should be the same. Therefore,

$\mathrm{\Delta}{t}_{e}^{2}=\mathrm{\Delta}{t}_{o}^{2}-\mathrm{\Delta}{x}^{2}$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}\mathrm{\Delta}{t}_{e}^{2}=\mathrm{\Delta}{t}_{o}^{2}-{v}^{2}\mathrm{\Delta}{t}_{o}^{2}$

$\phantom{\rule{thickmathspace}{0ex}}\u27f9\phantom{\rule{thickmathspace}{0ex}}\mathrm{\Delta}{t}_{o}=(1-{v}^{2}{)}^{-1/2}\mathrm{\Delta}{t}_{e}$

which is not the same relation. What is wrong with my reasoning?

asked 2022-07-17

Is there an easy way to show that ${x}^{2}-{t}^{2}=1/{g}^{2}$ for a (relativistic) body undergoing acceleration $g$?

asked 2022-07-14

If there is a non-zero expectation value for the Higgs boson even in "vacuum", since the Higgs boson has a mass unlike photons, then I would expect it to have a rest frame.

So why doesn't a non-zero expectation value for the Higgs boson not only break electroweak symmetry, but also break Lorentz symmetry?

So why doesn't a non-zero expectation value for the Higgs boson not only break electroweak symmetry, but also break Lorentz symmetry?