Finding unknown in log equation

I was given a log equation:

$D=10\mathrm{log}(I/{I}_{0})$

$I$ is the unknown in this case, ${I}_{0}={10}^{-12}$ and $D=89.3$

I did the following steps:

$\begin{array}{rl}\text{}89.3& =10\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\\ \text{}\frac{89.3}{10}& =\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\\ \text{}8.93& =\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\end{array}$

I'm not quite sure how to isolate I after step 3, and I'm also unsure if dividing $89.3/10$ is correct as well. So how can I find the unknown ($I$)?

I was given a log equation:

$D=10\mathrm{log}(I/{I}_{0})$

$I$ is the unknown in this case, ${I}_{0}={10}^{-12}$ and $D=89.3$

I did the following steps:

$\begin{array}{rl}\text{}89.3& =10\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\\ \text{}\frac{89.3}{10}& =\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\\ \text{}8.93& =\mathrm{log}\left(\frac{I}{{10}^{-12}}\right)\end{array}$

I'm not quite sure how to isolate I after step 3, and I'm also unsure if dividing $89.3/10$ is correct as well. So how can I find the unknown ($I$)?