I am given the equation: x^ay^b=6 Using implicit differentiation I find that the derivative of the equation with respect to y gives: (d)/(dx)(y)=−(ay)/(bx). However when I attempt to differentiate the "regular" way I don`t seem to reach the same answer. I would greatly appreciate someone walking me through the problem.

crazygbyo

crazygbyo

Answered question

2022-08-11

I am given the equation: x a y b = 6
Using implicit differentiation I find that the derivative of the equation with respect to y gives: d d x ( y ) = a y b x . However when I attempt to differentiate the "regular" way I don`t seem to reach the same answer. I would greatly appreciate someone walking me through the problem.

Answer & Explanation

kidoceanoe

kidoceanoe

Beginner2022-08-12Added 15 answers

then we get
a x a 1 y b + x a b y b 1 y = 0
you must use the product and chain rule:
( u v ) = u v + u v
and since
y = y ( x )
the first derivative is given by
y ( x )
( x a ) = a x a 1 ( x )
and
math xmlns="http://www.w3.org/1998/Math/MathML" > ( y ( x ) b ) = b y ( x ) b 1 y ( x )
nabakhi72

nabakhi72

Beginner2022-08-13Added 4 answers

Thank you for the help!

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