If x is invested at 7%, then 22000−x is invested at 6%.

The annual return is $1420 so we can write:

\(\displaystyle{0.07}{x}+{0.06}{\left({22000}−{x}\right)}={1420}\)

Solve for x:

\(\displaystyle{0.07}{x}+{1320}−{0.06}{x}={1420}\)

\(\displaystyle{0.01}{x}+{1320}={1420}\)

\(\displaystyle{0.01}{x}={100}\)

\(\displaystyle{x}=\frac{{100}}{{0.01}}\)

\(\displaystyle{x}={10000}\)

So, the executive invested $10,000 at 7% and $12,000 at 6%.

The annual return is $1420 so we can write:

\(\displaystyle{0.07}{x}+{0.06}{\left({22000}−{x}\right)}={1420}\)

Solve for x:

\(\displaystyle{0.07}{x}+{1320}−{0.06}{x}={1420}\)

\(\displaystyle{0.01}{x}+{1320}={1420}\)

\(\displaystyle{0.01}{x}={100}\)

\(\displaystyle{x}=\frac{{100}}{{0.01}}\)

\(\displaystyle{x}={10000}\)

So, the executive invested $10,000 at 7% and $12,000 at 6%.