Consider the polynomial f(x)=x^3+ax+b, where a and b are constants. If f(x+1004) leaves a remainder of 36 upon division by x+1005, and f(x+1005) leaves a remainder of 42 upon division by x+1004, what is the value of a+b?

Lokubovumn

Lokubovumn

Answered question

2022-08-09

Consider the polynomial f ( x ) = x 3 + a x + b, where a and b are constants. If f ( x + 1004 ) leaves a remainder of 36 upon division by x + 1005, and f ( x + 1005 ) leaves a remainder of 42 upon division by x + 1004, what is the value of a + b?

Answer & Explanation

Jaiden Gould

Jaiden Gould

Beginner2022-08-10Added 11 answers

By assumption we have
(1) f ( x + 1004 ) = ( x + 1005 ) Q ( x ) + 36
and
(2) f ( x + 1005 ) = ( x + 1004 ) S ( x ) + 42
so let x = 1005 in (1) gives
f ( 1 ) = 1 a + b = 36
and let x = 1004 in (2) gives
f ( 1 ) = 1 + a + b = 42
hence
a = 2 , b = 39

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