# Anonymous Anonymous Asked 10mths ago. A college student earned $8900 during summer vacation working as a waiter in a popular restaurant. Part was inve postillan4 2021-01-13 Answered Anonymous Anonymous Asked 10mths ago. A college student earned$8900 during summer vacation working as a waiter in a popular restaurant. Part was invested at 10% simple interest and the remainder at 6% simple interest. At the end of one year, the student had earned $674 interest. How much was invested at 10%? You can still ask an expert for help Expert Community at Your Service • Live experts 24/7 • Questions are typically answered in as fast as 30 minutes • Personalized clear answers Solve your problem for the price of one coffee • Available 24/7 • Math expert for every subject • Pay only if we can solve it ## Expert Answer Benedict Answered 2021-01-14 Author has 108 answers If x is invested at 6%, then $8900-x$ is invested at 10%. The interest earned in one year is$674 so we can write:
$0.06x+0.10\left(8900-x\right)=674$
Solve for x:
$0.06x+890-0.10x=674$
$-0.04x+89=674$
$-0.04x=-216$
$x=5400$
So, $8900-5400=\mathrm{}3500$ was invested at 10%.