h(x) = x^3 + x^2 - 9x - 9 Express h(x) as a product of linear factors

elfmo20

elfmo20

Answered question

2022-08-14

Answer & Explanation

alenahelenash

alenahelenash

Expert2023-05-29Added 556 answers

To express the polynomial h(x)=x3+x29x9 as a product of linear factors, we can use the fact that -3 is a zero of the polynomial.
When a polynomial has a zero c, it means that (xc) is a factor of the polynomial. Therefore, we can divide h(x) by (x(3)) or (x+3) to find the other factor.
Let's perform long division to find the other factor:
x 2 + 4 x + 3 x + 3 x 3 + x 2 9 x 9 x 3 + 3 x 2 2 x 2 9 x 2 x 2 6 x 3 x 9 3 x 9 0
The result of the division is x2+4x+3, which represents the other factor.
Now we can express h(x) as a product of linear factors:
h(x)=(x+3)(x2+4x+3)
Therefore, the polynomial h(x) can be written as the product of the linear factors (x+3) and (x2+4x+3).

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