What is the vertex of the function x^2 - 6x + 8 = 0?

moiraudjpdn
2022-08-08
Answered

What is the vertex of the function x^2 - 6x + 8 = 0?

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kilinumad

Answered 2022-08-09
Author has **21** answers

I think you mean x^2 - 6x + 8 = y

To find the x interecepts, make y = 0:

(x - 2)(x - 4) =0

x = 2, 4

So the x intercepts are (2, 0), (4, 0).

Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8).

Now for the vertex, take the derivative and set it to 0:

2x - 6 = 0

x = 3

Now plug that into the original equation;

9 - 18 + 8 = 0

= -1

So the vertex is at (3, -1)

To find the x interecepts, make y = 0:

(x - 2)(x - 4) =0

x = 2, 4

So the x intercepts are (2, 0), (4, 0).

Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8).

Now for the vertex, take the derivative and set it to 0:

2x - 6 = 0

x = 3

Now plug that into the original equation;

9 - 18 + 8 = 0

= -1

So the vertex is at (3, -1)

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