# What is the vertex of the function x^2 - 6x + 8 = 0?

What is the vertex of the function x^2 - 6x + 8 = 0?
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Dominic Paul
I think you mean x^2 - 6x + 8 = y
To find the x interecepts, make y = 0:
(x - 2)(x - 4) =0
x = 2, 4
So the x intercepts are (2, 0), (4, 0).
Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8).
Now for the vertex, take the derivative and set it to 0:
2x - 6 = 0
x = 3
Now plug that into the original equation;
9 - 18 + 8 = 0
= -1
So the vertex is at (3, -1)