$f(x)=\sqrt{2x}+6$

Passafaromx
2022-08-08
Answered

Determine the domain for this function:

$f(x)=\sqrt{2x}+6$

$f(x)=\sqrt{2x}+6$

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Kelton Glover

Answered 2022-08-09
Author has **17** answers

Domain is all values that x can take on

for this function, if $f(x)=\sqrt{2x}+6$, then x is all real numbers

if $f(x)=\sqrt{2x}+6$, then x will be all real numbers >= zero because you square root a negative number becomes an imaginary number

for this function, if $f(x)=\sqrt{2x}+6$, then x is all real numbers

if $f(x)=\sqrt{2x}+6$, then x will be all real numbers >= zero because you square root a negative number becomes an imaginary number

Yair Valentine

Answered 2022-08-10
Author has **6** answers

You can rewrite the function as:

$y=\sqrt{2x}+6$

The domain of this function, is all the values of x that make the function valid. One thing to note, is that you cannot take the square root of a negative number, because then you're dealing with imaginary numbers, so to get the domain, solve the following:

$2x\ge 0\leftarrow $ solve this for x, divide both sides by 2

$x\ge 0$

So the domain is all real numbers, or all x values greater than or equal to zero.

$y=\sqrt{2x}+6$

The domain of this function, is all the values of x that make the function valid. One thing to note, is that you cannot take the square root of a negative number, because then you're dealing with imaginary numbers, so to get the domain, solve the following:

$2x\ge 0\leftarrow $ solve this for x, divide both sides by 2

$x\ge 0$

So the domain is all real numbers, or all x values greater than or equal to zero.

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