Solve the equations using logs: (1.45)^x =25 2/7 = (0.6)^(2t) 500 = 25(1.1)^(3x)

Yair Valentine

Yair Valentine

Answered question

2022-08-07

Solve the equations using logs:
(1.45)x =25
2 / 7 = ( 0.6 ) 2 t
500 = 25 ( 1.1 ) 3 x

Answer & Explanation

wietselau

wietselau

Beginner2022-08-08Added 28 answers

ln ( 1.45 ) x = ln ( 25 )
x ln ( 1.45 ) = ln ( 25 )
x = ln ( 25 ) ln ( 1.45 ) = 3.218 0.3715 = 8.663
ln ( 2 / 7 ) = 2 t ln ( .6 )
2 t = ln ( 2 ) ln ( 7 ) ln ( 0.6 ) = 2.4524
t= 1.276
500 = 25 ( 1.1 ) 3 x
20 = ( 1.1 ) 3 x
ln ( 20 ) = 3 x ln ( 1.1 )
ln ( 20 ) ln ( 1.1 ) = 3 x = 31.431
x= 10.443
Massatfy

Massatfy

Beginner2022-08-09Added 6 answers

( 1.45 ) x = 25 x . ln ( 1.45 ) = ln ( 25 ) x = ln ( 25 ) / ln ( 1.45 )
2 / 7 = ( 0.6 ) 2 t ln ( 2 / 7 ) = 2 t ln ( 0.6 ) t = ln ( 2 / 7 ) / ln ( ( 0.6 ) 2 )
500 = 25 ( 1.1 ) 3 x ln ( 500 ) = ln ( 25 ) + 3 x ln ( 1.1 )
ln ( 500 ) ln ( 25 ) = x ln ( ( 1.1 ) 3 )
ln ( 500 / 25 ) = x ln ( ( 1.1 ) 3 )
ln ( 20 ) = x ln ( ( 1.1 ) 3 )
x = ln ( 20 ) / ln ( ( 1.1 ) 3 )

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