# An employment agency in temporary construction help pays heavy equipment operators $140 per day and general laborers$90 per day. If thirty-five people were hired and the payroll was $3950, how many heavy equipment operators were employed? How many laborers? Question Algebra foundations asked 2020-11-29 An employment agency in temporary construction help pays heavy equipment operators$140 per day and general laborers $90 per day. If thirty-five people were hired and the payroll was$3950, how many heavy equipment operators were employed? How many laborers? 2020-11-30
Let x be the number of operators and y be the number of laborers.
Thirty-five people were hired so:
$$\displaystyle{x}+{y}={35}{\left({1}\right)}$$
The payroll was $3950 so: $$\displaystyle{140}{x}+{90}{y}={3950}{\left({2}\right)}$$ Solve for yy using (1) to obtain (3): $$\displaystyle{y}={35}−{x}{\left({3}\right)}$$ Substitute (3) to (2) and solve for x: $$\displaystyle{140}{x}+{90}{\left({35}−{x}\right)}={3950}$$ $$\displaystyle{140}{x}+{3150}−{90}{x}={3950}$$ $$\displaystyle{50}{x}+{3150}={3950}$$ $$\displaystyle{50}{x}={800}$$ $$\displaystyle{x}={16}$$ Solve for y using (3): $$\displaystyle{y}={35}−{16}$$ $$\displaystyle{y}={19}$$ So, there were 16 operators and 19 laborers. ### Relevant Questions asked 2021-01-19 A bicycle with tires of radius r=15 inches is being ridden by a boy at a constant speed - the tires are making five rotations per second. How many miles will he ride in minutes? (1mi = 5280 ft) asked 2020-10-28 RJ’s Plumbing and Heating charges$55 plus $40 per hour for emergency service. Gary remembers being billed over$100 for an emergency call. How long was RJ’s there? On a recent day, a Euro was equal to about 1.2 American dollars. Write an expression which estimates the number of dollars in x Euros. Then estimate the number of American dollars equal to 25 Euros. A salesperson earns $50 a day plus 12% commission on sales over$200. If her daily earnings are \$76.88, how much money in merchandise did she sell? Researchers have asked whether there is a relationship between nutrition and cancer, and many studies have shown that there is. In fact, one of the conclusions of a study by B. Reddy et al., “Nutrition and Its Relationship to Cancer” (Advances in Cancer Research, Vol. 32, pp. 237-345), was that “...none of the risk factors for cancer is probably more significant than diet and nutrition.” One dietary factor that has been studied for its relationship with prostate cancer is fat consumption. On the WeissStats CD, you will find data on per capita fat consumption (in grams per day) and prostate cancer death rate (per 100,000 males) for nations of the world. The data were obtained from a graph-adapted from information in the article mentioned-in J. Robbins’s classic book Diet for a New America (Walpole, NH: Stillpoint, 1987, p. 271). For part (d), predict the prostate cancer death rate for a nation with a per capita fat consumption of 92 grams per day. a) Construct and interpret a scatterplot for the data. b) Decide whether finding a regression line for the data is reasonable. If so, then also do parts (c)-(f). c) Determine and interpret the regression equation. d) Make the indicated predictions. e) Compute and interpret the correlation coefficient. f) Identify potential outliers and influential observations. There are four people at a party. Each person shakes hands only once with every other person. How many handshakes occur? The IRS reported that as of April 17, 2015, it had received 132 million tax returns for 2014. Of these, 90% were filed electronically. How many of the returns were filed electronically? Round to the nearest million.   1. A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 144 students who averaged 44.7 texts per day. The standard deviation was 16.5 texts. a. To compute the confidence interval use a ? z t distribution. b. With 98% confidence the population mean number of texts per day is between and texts. c. If many groups of 144 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population number of texts per day and about percent will not contain the true population mean number of texts per day. 2. You want to obtain a sample to estimate how much parents spend on their kids birthday parties. Based on previous study, you believe the population standard deviation is approximately $$\displaystyle\sigma={40.4}$$ dollars. You would like to be 90% confident that your estimate is within 1.5 dollar(s) of average spending on the birthday parties. How many parents do you have to sample? n = 3. You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately $$\displaystyle\sigma={57.5}$$. You would like to be 95% confident that your estimate is within 0.1 of the true population mean. How large of a sample size is required?