Solve. sum_(n=1)^infty ntimes ((ln 2)^n)/(n!)

ljudskija7s

ljudskija7s

Answered question

2022-08-03

Solve. n = 1 n × ( ln 2 ) n n !

Answer & Explanation

Brennan Parks

Brennan Parks

Beginner2022-08-04Added 14 answers

write as ln ( 2 ) n = 1 ( ln ( 2 ) ) n 1 / ( n 1 ) ! = ln ( 2 ) n = 0 ( ln ( 2 ) ) n / n !
Then we can see the similarity between this and the series for e x
e x = n = 0 x n / n !
Comparing:
= ln ( 2 ) e ln ( 2 ) = 2 ln ( 2 )

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