musicintimeln
2022-08-05
Answered

Determine: $(2{b}^{4}{)}^{-1}$

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kilinumad

Answered 2022-08-06
Author has **21** answers

Step 1

The rule for raising a power to a power is that you multiply the exponents. Combining that with the Distributive Property yeilds the following:

$(A{B}^{M}{)}^{N}={A}^{N}{B}^{MN}$

In this case, $A=2,\text{}B=b,\text{}M=4,\text{}N=-1$

Also, the rule for negative expontents is that they go in the denominator as follows:

${A}^{-M}=\frac{1}{{A}^{M}}$

Use these two formulas to get to your answer.

The rule for raising a power to a power is that you multiply the exponents. Combining that with the Distributive Property yeilds the following:

$(A{B}^{M}{)}^{N}={A}^{N}{B}^{MN}$

In this case, $A=2,\text{}B=b,\text{}M=4,\text{}N=-1$

Also, the rule for negative expontents is that they go in the denominator as follows:

${A}^{-M}=\frac{1}{{A}^{M}}$

Use these two formulas to get to your answer.

Leypoldon

Answered 2022-08-07
Author has **8** answers

Step 1

$(1{b}^{4}{)}^{-1}={2}^{-1}\times {b}^{4\times -1}\phantom{\rule{0ex}{0ex}}=\frac{1}{2}\times \frac{1}{{b}^{4}}\phantom{\rule{0ex}{0ex}}=\frac{1}{2\times {b}^{4}}$

$(1{b}^{4}{)}^{-1}={2}^{-1}\times {b}^{4\times -1}\phantom{\rule{0ex}{0ex}}=\frac{1}{2}\times \frac{1}{{b}^{4}}\phantom{\rule{0ex}{0ex}}=\frac{1}{2\times {b}^{4}}$

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