 # 1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle. 2.a square has an area of 16 yd^2. what is the perimeterof the square? 3.The area of a triangle is 112 m^2. If the length of thebase is 16 m, what is the height? 4.What is the maximum area for a rectangle with a perimeter of 40centimeters? 5.The length of a rectangle is 2 in. more than the width. Ifthe perimeter is 24 in., find the area of the rectangle. logosdepmpe 2022-08-04 Answered
1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle.
2.a square has an area of $16y{d}^{2}$. what is the perimeterof the square?
3.The area of a triangle is $112{m}^{2}$. If the length of thebase is 16 m, what is the height?
4.What is the maximum area for a rectangle with a perimeter of 40centimeters?
5.The length of a rectangle is 2 in. more than the width. If the perimeter is 24 in., find the area of the rectangle.
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1) It is a $6×9$ rectangle, so the area is $6\ast 9=54i{n}^{2}$
2) It is a $4×4$ square so the perimeter is 16in
3) 112/8 = 14 so the height of the triangle is 14m
4) The rectangle with the greatest area is a square, so itwould be a $10×10$ square with a area of 100cm
5) It is a $5×7$ rectange, so the area is $5\ast 7=35i{n}^{2}$

We have step-by-step solutions for your answer! wendi1019gt
1. let x be witdth
3+x=length
P=2L+2W,
2x+2(x+3)=30
4x+6=30, x=6 inches width
3+x=3+6=9 inches length
$A=lw=9\left(6\right)=54i{n}^{2}$
2. $A={x}^{2},16={x}^{2},x=4yd$
P=4s=4(4)=16yd
3. area triangle
$A=\frac{1}{2}bh,112=\frac{1}{2}\left(16\right)h$
224=16h, h=14m
4.P=2l+2w,40=2l+2w,
l+w=20, l=20-w
$A=lw=\left(20-w\right)w=20w-{w}^{2}$
find vertex
$w=-\frac{b}{2a}=-\frac{20}{-2}=10$
$A\left(10\right)=20\left(10\right)-{10}^{2}=200-100=100c{m}^{2}$
5. let x be width
2+x = length
p=2l+2w, 24=2(2+x)+2x
2x+2x+4=24, 4x=20, x=5 in width
length 2+x=2+5=7in
now area
$A=7\left(5\right)=35i{n}^{2}$

We have step-by-step solutions for your answer!