1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle. 2.a square has an area of 16 yd^2. what is the perimeterof the square? 3.The area of a triangle is 112 m^2. If the length of thebase is 16 m, what is the height? 4.What is the maximum area for a rectangle with a perimeter of 40centimeters? 5.The length of a rectangle is 2 in. more than the width. Ifthe perimeter is 24 in., find the area of the rectangle.

logosdepmpe

logosdepmpe

Answered question

2022-08-04

1.the length of a rectangle is 3 in. more than the width. if the perimeter is 30 in., find the area of a rectangle.
2.a square has an area of 16 y d 2 . what is the perimeterof the square?
3.The area of a triangle is 112 m 2 . If the length of thebase is 16 m, what is the height?
4.What is the maximum area for a rectangle with a perimeter of 40centimeters?
5.The length of a rectangle is 2 in. more than the width. If the perimeter is 24 in., find the area of the rectangle.

Answer & Explanation

Alejandra Blackwell

Alejandra Blackwell

Beginner2022-08-05Added 14 answers

1) It is a 6 × 9 rectangle, so the area is 6 9 = 54 i n 2
2) It is a 4 × 4 square so the perimeter is 16in
3) 112/8 = 14 so the height of the triangle is 14m
4) The rectangle with the greatest area is a square, so itwould be a 10 × 10 square with a area of 100cm
5) It is a 5 × 7 rectange, so the area is 5 7 = 35 i n 2
wendi1019gt

wendi1019gt

Beginner2022-08-06Added 7 answers

1. let x be witdth
3+x=length
P=2L+2W,
2x+2(x+3)=30
4x+6=30, x=6 inches width
3+x=3+6=9 inches length
A = l w = 9 ( 6 ) = 54 i n 2
2. A = x 2 , 16 = x 2 , x = 4 y d
P=4s=4(4)=16yd
3. area triangle
A = 1 2 b h , 112 = 1 2 ( 16 ) h
224=16h, h=14m
4.P=2l+2w,40=2l+2w,
l+w=20, l=20-w
A = l w = ( 20 w ) w = 20 w w 2
find vertex
w = b 2 a = 20 2 = 10
A ( 10 ) = 20 ( 10 ) 10 2 = 200 100 = 100 c m 2
5. let x be width
2+x = length
p=2l+2w, 24=2(2+x)+2x
2x+2x+4=24, 4x=20, x=5 in width
length 2+x=2+5=7in
now area
A = 7 ( 5 ) = 35 i n 2

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