An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was$423, $468, $403, $222 . Compute the range, samplevariance, and sample standard deviation cost of repair.
An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was$423, $468, $403, $222 . Compute the range, samplevariance, and sample standard deviation cost of repair.
asigurato7
2022-07-31
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Answers (1)
Bradley Sherman
Answered 2022-08-01
Author has 17 answers
Step 1
The range of a data set is the highest data value minus the lowest data value. Here, the range of the cost of repair is .
The mean of the given data set for the cost of repair is .
If there are n data points, then the Variance = sum of the squares of (Data points - mean) divided by .
Here, the difference of the data points from the mean are . Hence the variance is .
Step 2
The standard deviation is the square root of the average squared deviation from the mean.
Here, the standard deviation is ( on rounding off to 2 decimal places).
The range of a data set is the highest data value minus the lowest data value. Here, the range of the cost of repair is .
The mean of the given data set for the cost of repair is .
If there are n data points, then the Variance = sum of the squares of (Data points - mean) divided by .
Here, the difference of the data points from the mean are . Hence the variance is .
Step 2
The standard deviation is the square root of the average squared deviation from the mean.
Here, the standard deviation is ( on rounding off to 2 decimal places).
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