Joanna Mueller
2022-07-29
Answered

${v}^{2}+3v-28=0$

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Kitamiliseakekw

Answered 2022-07-30
Author has **23** answers

Use the quadratic equation

$x=\frac{-b\pm \sqrt{({b}^{2}-4ac)}}{2a}$

a=1, b=3, c=-28

x=4, x=-7

$x=\frac{-b\pm \sqrt{({b}^{2}-4ac)}}{2a}$

a=1, b=3, c=-28

x=4, x=-7

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If

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2. ${a}^{2}={b}^{2}+c=6$ (this is not symmetric equation)

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Then find the value of ${a}^{4}+{b}^{4}+{c}^{4}$

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Then find the value of ${a}^{4}+{b}^{4}+{c}^{4}$

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