Solve for x where x is a real number. squareroot of (7x+36) - squareroot of (x+21) = 3

Baladdaa9 2022-08-01 Answered
Solve for x where x is a real number. squareroot of (7x+36) - squareroot of (x+21) = 3
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Answers (1)

suchonos6r
Answered 2022-08-02 Author has 14 answers
squareroot of (7x+36) - squareroot of (x+21) = 3
squaring on both sides
7x+36+x+21 -2squareroot of (7x+36)*squareroot of (x+21) = 9
8x+48=2squareroot of (7x+36)*squareroot of (x+21)
4x+24=squareroot of (7x+36)*squareroot of (x+21)
squaring on both sides
(4x+24)^2=(7x+36)*(x+21)
=>16x^2+576+192x=7x^2+183x+756
=>9x^2 +9x-180=0
=>x^2+x-20=0
==>x=4,-5
x cannot be -5
so x is 4
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