# Find the length and direction of utimes v and vtimes u u = 2i - 2j + 4k, v = -i + j - 2k

Find the length and direction of $u×v$ and $v×u$
u = 2i - 2j + 4k, v = -i + j - 2k
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kuglatid4
First we find $u×v=|\begin{array}{ccc}i& j& k\\ 2& -2& 4\\ -1& 1& -2\end{array}|$
=i(4-4)-j(-4+4)+k(2-2)
=0
and $v×u=|\begin{array}{ccc}i& j& k\\ -1& 1& -2\\ 2& -2& 4\end{array}|$
=i(4-4)-j(-4+4)+k(2-2)
=0
$\therefore$ The length of the $u×v$ and$v×u$ is'zero', and both are have the same direction.