Solve.

$(3x+10{)}^{1/2}=10-x$

$(3x+10{)}^{1/2}=10-x$

Ciara Rose
2022-07-30
Answered

Solve.

$(3x+10{)}^{1/2}=10-x$

$(3x+10{)}^{1/2}=10-x$

You can still ask an expert for help

juicilysv

Answered 2022-07-31
Author has **17** answers

Square both sides to get rid of the square root.

$3x+10=(10-x{)}^{2}$

Foil

$3x+10=100-20x+{x}^{2}$

Move everything to one side to have one side equal 0.

$0={x}^{2}-20-3x+100-10$

$0={x}^{2}-23x+90$

Factor and solve for x.

0=(x - 18)(x - 5)

x - 18=0 and x- 5=0

x=18 x= 5

$3x+10=(10-x{)}^{2}$

Foil

$3x+10=100-20x+{x}^{2}$

Move everything to one side to have one side equal 0.

$0={x}^{2}-20-3x+100-10$

$0={x}^{2}-23x+90$

Factor and solve for x.

0=(x - 18)(x - 5)

x - 18=0 and x- 5=0

x=18 x= 5

Aphroditeoq

Answered 2022-08-01
Author has **2** answers

$3x+10=(10-x{)}^{2}$

$3x+10=(-x+10{)}^{2}$

3x+10=(-x*-x-x*10+10*-x+10*10)

$3x+10=({x}^{2}-20x+100)$

$3x+10={x}^{2}-20x+100$

${x}^{2}-20x+100=3x+10$

${x}^{2}-20x+100-3x=10$

${x}^{2}-23x+100=10$

${x}^{2}-23x=-100+10$

${x}^{2}-23x=-90$

${x}^{2}-23x+90=0$

(x )(x )=0

(x-5)(x-18)=0

x-5=0

x-18=0

x=5

x=18

ANSWER x=5,18

$3x+10=(-x+10{)}^{2}$

3x+10=(-x*-x-x*10+10*-x+10*10)

$3x+10=({x}^{2}-20x+100)$

$3x+10={x}^{2}-20x+100$

${x}^{2}-20x+100=3x+10$

${x}^{2}-20x+100-3x=10$

${x}^{2}-23x+100=10$

${x}^{2}-23x=-100+10$

${x}^{2}-23x=-90$

${x}^{2}-23x+90=0$

(x )(x )=0

(x-5)(x-18)=0

x-5=0

x-18=0

x=5

x=18

ANSWER x=5,18

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