# Solve. (3x+10)^(1/2)=10-x

Solve.
$\left(3x+10{\right)}^{1/2}=10-x$
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juicilysv
Square both sides to get rid of the square root.
$3x+10=\left(10-x{\right)}^{2}$
Foil
$3x+10=100-20x+{x}^{2}$
Move everything to one side to have one side equal 0.
$0={x}^{2}-20-3x+100-10$
$0={x}^{2}-23x+90$
Factor and solve for x.
0=(x - 18)(x - 5)
x - 18=0 and x- 5=0
x=18 x= 5
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Aphroditeoq
$3x+10=\left(10-x{\right)}^{2}$
$3x+10=\left(-x+10{\right)}^{2}$
3x+10=(-x*-x-x*10+10*-x+10*10)
$3x+10=\left({x}^{2}-20x+100\right)$
$3x+10={x}^{2}-20x+100$
${x}^{2}-20x+100=3x+10$
${x}^{2}-20x+100-3x=10$
${x}^{2}-23x+100=10$
${x}^{2}-23x=-100+10$
${x}^{2}-23x=-90$
${x}^{2}-23x+90=0$
(x )(x )=0
(x-5)(x-18)=0
x-5=0
x-18=0
x=5
x=18