(7x)/(x^2+2xy+y^2)+(3x)/(x^2+xy)

Baladdaa9 2022-08-01 Answered
7 x x 2 + 2 x y + y  + 3 x x 2 + x y = 0
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Answers (2)

Dominique Ferrell
Answered 2022-08-02 Author has 18 answers
7 x x 2 + 2 x y + y + 3 x x 2 + x y = 0
7 x x 2 + 2 x y + y = 3 x x 2 + x y
doing cross multiplication:
7 x ( x 2 + x y ) = ( x 2 + 2 x y + y ) ( 3 x )
7 x 3 + 7 x 2 y = 3 x 3 6 x 2 y 3 x y
isolate anything with y on one side and rest on other
7 x 2 y + 6 x 2 y + 3 x y = 3 x 3 7 x 3
13 x 2 y + 3 x y = 10 x 3
y ( 13 x 2 + 3 x ) = 10 x 3
y = 10 x 3 13 x 2 + 3 x
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Bruno Thompson
Answered 2022-08-03 Author has 9 answers
( 7 x ) / ( x 2 + 2 x y + y ) + ( 3 x ) / ( x 2 + x y ) = 0
( 7 x ) / ( x 2 + 2 x y + y ) + ( 3 x ) / ( x ( x ) + x ( y ) ) = 0
( 7 x ) / ( x 2 + 2 x y + y ) + ( 3 x ) / ( x ( x + y ) ) = 0
Least common denominator: x ( x 2 + 2 x y + y ) ( x + y )
( 7 x ) / ( x 2 + 2 x y + y ) x ( x 2 + 2 x y + y ) ( x + y ) + ( 3 x ) / ( x ( x + y ) ) x ( x 2 + 2 x y + y ) ( x + y ) = 0 x ( x 2 + 2 x y + y ) ( x + y )
10 x 3 + 13 x 2 y + 3 x y = 0 x ( x 2 + 2 x y + y ) ( x + y )
10 x 3 + 13 x 2 y + 3 x y = 0
13 x 2 y + 3 x y = 10 x 3
13 x 2 y + 3 x y + 10 x 3 = 0
x ( 10 x 2 ) + x ( 13 x y ) + x ( 3 y ) = 0
x ( 10 x 2 + 13 x y + 3 y ) = 0
x=0
10 x 2 + 13 x y + 3 y = 0
13 x y + 3 y = 10 x 2
y ( 13 x ) + y ( 3 ) = 10 x 2
y ( 13 x + 3 ) = 10 x 2
( y ( 13 x + 3 ) ) / ( 13 x + 3 ) = ( 10 x 2 ) / ( 13 x + 3 )
y = ( 10 x 2 ) / ( 13 x + 3 )
ANSWER y = 0 , ( 10 x 2 ) / ( 13 x + 3 )
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