Write the slope-intercept form of the equation of the line described.

Through: (2,3), parallel to $y=\frac{5}{2}x-1$

Through: (2,3), parallel to $y=\frac{5}{2}x-1$

equissupnica7
2022-08-01
Answered

Write the slope-intercept form of the equation of the line described.

Through: (2,3), parallel to $y=\frac{5}{2}x-1$

Through: (2,3), parallel to $y=\frac{5}{2}x-1$

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Caylee Davenport

Answered 2022-08-02
Author has **14** answers

Step 1

Passes through (2, 3) and parallel to $y=\frac{5}{2}x-1$

Therefore, slope of the line through (2,3) is $m=\frac{-2}{5}$

Step 2

Eq. of the line is $\frac{y-3}{x-2}=\frac{-2}{5}$

$\Rightarrow 5y-15=-2x+4$

$\Rightarrow 5y+2x=19$

$\therefore y=\frac{-2x}{5}+\frac{19}{5}$

Passes through (2, 3) and parallel to $y=\frac{5}{2}x-1$

Therefore, slope of the line through (2,3) is $m=\frac{-2}{5}$

Step 2

Eq. of the line is $\frac{y-3}{x-2}=\frac{-2}{5}$

$\Rightarrow 5y-15=-2x+4$

$\Rightarrow 5y+2x=19$

$\therefore y=\frac{-2x}{5}+\frac{19}{5}$

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