Write the slope-intercept form of the equation of the line described. Through: (2,3), parallel to y=5/2 x-1

Write the slope-intercept form of the equation of the line described.
Through: (2,3), parallel to $y=\frac{5}{2}x-1$
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Step 1
Passes through (2, 3) and parallel to $y=\frac{5}{2}x-1$
Therefore, slope of the line through (2,3) is $m=\frac{-2}{5}$
Step 2
Eq. of the line is $\frac{y-3}{x-2}=\frac{-2}{5}$
$⇒5y-15=-2x+4$
$⇒5y+2x=19$
$\therefore y=\frac{-2x}{5}+\frac{19}{5}$
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