Sound level L_P in units of decibles (dB)is determined by: L_P = 20log_(10)(P/(P_(0))) where p is the sound pressure of the sound, and p_0 = 20 * 10^(-6) Pa is a referencesound pressure (the sound pressure when L_P = 0dB). Determine the sound pressure of 90 dB noise (noisegenerated by a passing truck). By how many times the soundpressure of the truck is larger (louder) than the sound pressureduring normal conversation where the loudness is 65 dB?

comAttitRize8 2022-07-26 Answered
Sound level L P in units of decibles (dB)is determined by:
L P = 20 log 10 ( P P 0 )
where p is the sound pressure of the sound, and p 0 = 20 10 6 P a is a reference sound pressure (the sound pressure when L P = 0 d B). Determine the sound pressure of 90 dB noise (noisegenerated by a passing truck). By how many times the soundpressure of the truck is larger (louder) than the sound pressureduring normal conversation where the loudness is 65 dB?
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (1)

Urijah Hahn
Answered 2022-07-27 Author has 13 answers
L p = 20 log ( P / 20 10 6 ) = 90
so, log ( P / 20 10 6 ) = 4.5
so, P = 0.6325 Pa
L p = L p (truck) - L p (norm.conv.)
so,
90 65 = 20 log ( P t / P n c )
so,
P / P c = 10 1.75 = 56.234 times
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions