Concentric with thw circle x^2+y^2+8x-3y+16=0 and touching the line 4x+3y=12

Brenton Dixon 2022-07-28 Answered
Concentric with thw circle x 2 + y 2 + 8 x 3 y + 16 = 0 and touching the line 4x+3y=12
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Answers (1)

Helena Howard
Answered 2022-07-29 Author has 12 answers
centre =( -4 ,1.5)
And tangent is 4x+3y =12
So radius is distance of tangent and centre
R = 16 + 10.5 12 5 = 3.5
So eqn is
( x + 4 ) 2 + ( y 1.5 ) 2 = 3.5 2 x 2 + y 2 + 8 x 3 y + 6 = 0 (ans)

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