 # Let v(t)=t^2-2t be the velocity, in feet per second, of an object at time t, in seconds. Shannon Andrews 2022-07-25 Answered
Let $v\left(t\right)={t}^{2}-2t$ be the velocity, in feet per second, of an object at time t, in seconds.
a What is the initial velocity initial velocity?
Initial velocity=?
b) When does the object have a velocity of zero? If there Is more than one time, list all answers in a comma separated list.
$t=?$
c) What is the meaning of the quantity v(4)? Select all that apply if more than one statement is correct.
A. This is how much the object has moved in 4 seconds.
B. This is the object's velocity in 4 hours
C. In this number of hours the velocity will be 4 t/sec.
D. This is the object's velocity in 4 seconds.
E. This is the average velocty of the object over the 4 second interval.
F. In this number of seconds the object will have moved 4 ft.
G. None of the above.
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Step 1
a) Initial velocity $=v\left(0\right)$
$={0}^{2}-2\cdot 0$
$=0$ feet per second
Step 2
b) $v\left(t\right)=0$
${t}^{2}-2t=0$
$t\left(t-2\right)=0$
$t=0,2$
Step 3
c) Correct option is D