# Find the unit vector along the line joining point (2, 4, 4) to point (-3,2,2).

Find the unit vector along the line joining point (2, 4, 4) to point (-3,2,2).
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Marshall Mcpherson
Vector from point 1 to point 2 is given by:
(-3-2,2-4,2-4) = (-5,-2,-2)
$length=\sqrt{{5}^{2}+{2}^{2}+{2}^{2}}=\sqrt{33}$
So unit vector is:
$\left(-5/\sqrt{33},-2/\sqrt{33},-2/\sqrt{33}\right)$