x(x-8) = 0 so, the zeros are at 0 and 8. min val = 0 max val = 8 Since a > 0, it has a minimum. The minimum value of f(x) is-16 when x is 4. The maximum and minimum of the parabola is thevertex.So, this is determined by finding the vertex x = -b/2a, thensubstituting x to find the value of f(x) b)
(2x - 1) (x + 5) = 0 So the zeros are at x = 1/2 and x=-5 Since a< 0, then it will have a maximum. Using the vertexformula again, we find the max is 121/8 when x is -9/4.