A rifle with a muzzle velocity of 2000 ft./sec. is fired horizontally at aheight of five feet above level ground. Ignoring air resistance,how far (nearest whole foot) does the bullet travel from the end ofthe muzzle of the rifle before it strikes the ground?

A rifle with a muzzle velocity of 2000 ft./sec. is fired horizontally at aheight of five feet above level ground. Ignoring air resistance,how far (nearest whole foot) does the bullet travel from the end ofthe muzzle of the rifle before it strikes the ground?
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Hassan Watkins
1. Find the time it takes for the bullet to fall to the ground.It's vertical displacement is independent from the horizontal displacement. e.g. if you dropped a bullet down to the ground atthe same time that you shot it, both would it the ground at thesame time.
$y\left(t\right)=1/2a{t}^{2}$
$y\left(t\right)=1/2\ast 32.17ft/{s}^{2}x{t}^{2}$
$y\left(t\right)=5ft=1/2\ast 32.17ft/{s}^{2}{t}^{2}$
t=0.558s
2. Take the time (t) for it to hit the ground, plug it in to thehorizontal displacement equation to get displacement
x(t) = 2000ft/s * t
x(0.558) = 2000*0.558 = 1116ft
Which is pretty close to c.1118ft