A coffee house has 20 pounds of a coffee that sells for $4 perpound. How many pounds of coffee that sells for $8 a pound shouldbe mixed with 20 pounds of the $ 4 per pound cofee to obtain ablend that will sell for $5 per pound? How much of the $5 per poundcoffee will there be?

Taniya Burns 2022-07-27 Answered
A coffee house has 20 pounds of a coffee that sells for $4 perpound. How many pounds of coffee that sells for $8 a pound shouldbe mixed with 20 pounds of the $ 4 per pound cofee to obtain ablend that will sell for $5 per pound? How much of the $5 per poundcoffee will there be?
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Answers (1)

Dominique Ferrell
Answered 2022-07-28 Author has 18 answers
type 1 coffee: sells for $4 per pound
type 2 coffee: sells for $8 per pound
let x pounds of type 2 coffee is mixed with20 pounds of type 1 coffee to obtain a blend that will sell for $5 per pound.
selling price of type 1 coffee (20 pounds at a rate $4/pound) =20*4 = 80$
selling price of type 2 coffee (x pounds at a rate $8/pound) = x*8= 8x $
total coffee(type 1 + type 2) = (20 + x)pound if the blend sells for 5$ /pound then selling price = 5*(20 + x) =100 + 5x $
so we can say,
100 + 5x = 80 + 8x
8 x 5 x = 100 80 = 20
3 x = 20
x = 20 / 3 = 6.67
Answer: 6.67 pound of type 2 coffee(that sells for $8 per pound)

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