(3+4)11+24/8(6-4)

Greyson Landry
2022-07-26
Answered

(3+4)11+24/8(6-4)

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Seromaniaru

Answered 2022-07-27
Author has **12** answers

$(3+4)11+24/8(6-4)\phantom{\rule{0ex}{0ex}}77+24/16\phantom{\rule{0ex}{0ex}}77+\frac{3}{2}\phantom{\rule{0ex}{0ex}}\frac{154+3}{2}\phantom{\rule{0ex}{0ex}}\frac{157}{2}$

asked 2022-08-07

Find:

1. $\frac{mpk-{p}^{2}}{pm-pk}$

2. $\frac{p{m}^{2}-mk}{{k}^{2}+pm}$

3. $\frac{{p}^{2}-{m}^{2}}{{k}^{3}+mk-k}$

1. $\frac{mpk-{p}^{2}}{pm-pk}$

2. $\frac{p{m}^{2}-mk}{{k}^{2}+pm}$

3. $\frac{{p}^{2}-{m}^{2}}{{k}^{3}+mk-k}$

asked 2022-05-13

I've seen some equations and inequalities that have no solution. Examples of these are

$3m+4=3m-9$

$128y-10<128y-25$

$10t+45\ge 2(5t+23)$

The third example evaluates to

$10t+45\ge 10t+46$

Why do some equations or inequalities have no solution?

$3m+4=3m-9$

$128y-10<128y-25$

$10t+45\ge 2(5t+23)$

The third example evaluates to

$10t+45\ge 10t+46$

Why do some equations or inequalities have no solution?

asked 2022-02-05

How do you simplify $4z+11+9z+18$

asked 2022-07-27

Jason went swimming. He dives of the distance from the diving board to the end of the swimming pool. Then, he swims of the distance from the diving board to the end of the swimming pool. He estimated that he coveblack about of the distance from the diving board to the end of the swimming pool. Is Jason's estimate reasonable?

asked 2022-07-28

Part of understanding linear programming is knowing how to do the algebra to identify the points where you are using all of both items to either maximize profit or minimize loss.

So, to give you additional practice with the algebra of linear programming, do the following:

Step 1: If your last name ends in A-H, do problem #1. If your last name ends in I-P, do problem #2. If your last name ends in Q-Z, do problem #3.

Problem 1 – Use your class notes and textbook to solve for X1and X2:

$2{x}_{1}+4{x}_{1}=80$

$3{x}_{1}+1{x}_{2}=60$

Problem 2 – Use your class notes and textbook to solve for X1and X2:

$2{x}_{1}+4{x}_{2}=400$

$100{x}_{1}+50{x}_{2}=12$

Problem 3 – Use your class notes and textbook to solve for X1and X2:

$4{x}_{1}+6{x}_{2}=48$

$4{x}_{1}+2{x}_{2}=12$

Step 2: Once you have determined the answers for ${x}_{1}$ and ${x}_{2}$in each problem, count how many letters you have in your first and last name. The number of letters in your first name will equal the profit per item for ${x}_{1}$ and the number of letters in your last name will be the profit per item for ${x}_{2}$.

Then multiply the answer you came up with for ${x}_{1}$ by the number of letters in your first name, and then multiply the answer you came up with for ${x}_{2}$ by the number of letters in your last name.

Example: Both my first and last name are each 4 characters long. If ${x}_{1}$ is 10 and ${x}_{2}$ is 15, I would multiply (10*4) = $40 and (15*4) = $60. So, your profit for ${x}_{1}$ would be $40 and your profit for ${x}_{2}$ would be $60, for a total profit of $100.

Step 3: Answer the following questions:

a. Based on your last name, which problem (1, 2, or 3) did you solve? (value: 10 points)

b. What answer did you get for ${x}_{1}$? (value: 20 points)

c. What answer did you get for ${x}_{2}$? (value: 20 points)

d. Based on the number of characters in your first name, what profit did you get for ${x}_{1}$? (value: 20 points)

e. Based on the number of characters in your last name, what profit did you get for ${x}_{2}$? (value: 20 points)

f. What is the sum of your profits for ${x}_{1}$ and ${x}_{2}$? (value: 10 points)

So, to give you additional practice with the algebra of linear programming, do the following:

Step 1: If your last name ends in A-H, do problem #1. If your last name ends in I-P, do problem #2. If your last name ends in Q-Z, do problem #3.

Problem 1 – Use your class notes and textbook to solve for X1and X2:

$2{x}_{1}+4{x}_{1}=80$

$3{x}_{1}+1{x}_{2}=60$

Problem 2 – Use your class notes and textbook to solve for X1and X2:

$2{x}_{1}+4{x}_{2}=400$

$100{x}_{1}+50{x}_{2}=12$

Problem 3 – Use your class notes and textbook to solve for X1and X2:

$4{x}_{1}+6{x}_{2}=48$

$4{x}_{1}+2{x}_{2}=12$

Step 2: Once you have determined the answers for ${x}_{1}$ and ${x}_{2}$in each problem, count how many letters you have in your first and last name. The number of letters in your first name will equal the profit per item for ${x}_{1}$ and the number of letters in your last name will be the profit per item for ${x}_{2}$.

Then multiply the answer you came up with for ${x}_{1}$ by the number of letters in your first name, and then multiply the answer you came up with for ${x}_{2}$ by the number of letters in your last name.

Example: Both my first and last name are each 4 characters long. If ${x}_{1}$ is 10 and ${x}_{2}$ is 15, I would multiply (10*4) = $40 and (15*4) = $60. So, your profit for ${x}_{1}$ would be $40 and your profit for ${x}_{2}$ would be $60, for a total profit of $100.

Step 3: Answer the following questions:

a. Based on your last name, which problem (1, 2, or 3) did you solve? (value: 10 points)

b. What answer did you get for ${x}_{1}$? (value: 20 points)

c. What answer did you get for ${x}_{2}$? (value: 20 points)

d. Based on the number of characters in your first name, what profit did you get for ${x}_{1}$? (value: 20 points)

e. Based on the number of characters in your last name, what profit did you get for ${x}_{2}$? (value: 20 points)

f. What is the sum of your profits for ${x}_{1}$ and ${x}_{2}$? (value: 10 points)

asked 2022-06-19

How do you solve and graph $-13m>-26$ ?

asked 2022-06-28

How do you solve $\frac{1}{2}z<20$ ?