# Solve. 5(x^6+1)^4(6x^5)(3x+2)^3+3(3x+2)^2(3)(x^6+1)^5

Solve. $5\left({x}^{6}+1{\right)}^{4}\left(6{x}^{5}\right)\left(3x+2{\right)}^{3}+3\left(3x+2{\right)}^{2}\left(3\right)\left({x}^{6}+1{\right)}^{5}$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Mira Spears
$5\left({x}^{6}+1{\right)}^{4}\left(6{x}^{5}\right)\left(3x+2{\right)}^{3}+3\left(3x+2{\right)}^{2}\left(3\right)\left({x}^{6}+1{\right)}^{5}=\left({x}^{6}+1{\right)}^{4}\left(3x+2{\right)}^{2}\left(30{x}^{5}\ast \left(3x+2\right)+9\left({x}^{6}+1\right)\right)$
$=\left({x}^{6}+1\right)4\left(3x+2{\right)}^{2}\left(90{x}^{6}+60{x}^{5}+9{x}^{6}+9\right)$
$=\left({x}^{6}+1{\right)}^{4}\left(3x+2{\right)}^{2}\left(99{x}^{6}+60{x}^{5}+9\right)$

Shannon Andrews
$5\left({x}^{6}+1{\right)}^{4}\left(6{x}^{5}\right)\left(3x+2{\right)}^{3}+3\left(3x+2{\right)}^{2}\left(3\right)\left({x}^{6}+1{\right)}^{5}$
lets life less complicated. lets just label what'salike
$\left({x}^{6}+1\right)=a,\left(6{x}^{5}\right)=b,\left(3x+2\right)=c$
so now we got, $5{a}^{4}b{c}^{3}+3{c}^{2}3{a}^{5}\to 5{a}^{4}b{c}^{3}+9{c}^{2}{a}^{5}$
Now factor what's in common in both terms. ${a}^{4}{c}^{2}\left(5bc+9a\right)$
Now you are almost done. Now just substitute back the originalvalues into a,b,and c. And that should be your final answer