Solve with the quadratic formula.

$2{p}^{2}-4p=5$

$2{p}^{2}-4p=5$

Raegan Bray
2022-07-26
Answered

Solve with the quadratic formula.

$2{p}^{2}-4p=5$

$2{p}^{2}-4p=5$

You can still ask an expert for help

Raul Garrett

Answered 2022-07-27
Author has **14** answers

$2{p}^{2}-4p=5$

$2{p}^{2}-4p-5=0$

quadratic formula: $(-b\pm \sqrt{{b}^{2}}-4ac/2a)$

b = -4

a = 2

c =-5

$=-(-4)\pm {\sqrt{-4}}^{2}-4(2)(-5)/2(2)$

$=4\pm \sqrt{16}+40/4$

$=(4+\sqrt{56})/4$ or $(4-\sqrt{56})/4$

$2{p}^{2}-4p-5=0$

quadratic formula: $(-b\pm \sqrt{{b}^{2}}-4ac/2a)$

b = -4

a = 2

c =-5

$=-(-4)\pm {\sqrt{-4}}^{2}-4(2)(-5)/2(2)$

$=4\pm \sqrt{16}+40/4$

$=(4+\sqrt{56})/4$ or $(4-\sqrt{56})/4$

kadejoset

Answered 2022-07-28
Author has **2** answers

$2{p}^{2}-4p-5=0$

quadratic formula is $x=-b+/-({b}^{2}-4ac{)}^{.5}/2a$

b=-4

a=2

c=-5

thus

$x=-(-4)+/-((-4{)}^{2}-4\ast 2\ast (-5){)}^{.5}/2\ast 2)$

$x=(4+/-(16+40{)}^{.5})/4$

$x=(4+/-(56{)}^{.5})/4$

x= 4/4 +/- 7.48/4

x = 1 + 1.87 = 2.87 and x = 1 - 1.87 = -0.87

quadratic formula is $x=-b+/-({b}^{2}-4ac{)}^{.5}/2a$

b=-4

a=2

c=-5

thus

$x=-(-4)+/-((-4{)}^{2}-4\ast 2\ast (-5){)}^{.5}/2\ast 2)$

$x=(4+/-(16+40{)}^{.5})/4$

$x=(4+/-(56{)}^{.5})/4$

x= 4/4 +/- 7.48/4

x = 1 + 1.87 = 2.87 and x = 1 - 1.87 = -0.87

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